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msg/reply: Deduplicate TO: and CC: 

If a recipient is already in TO:, there's no need to also put them in CC:
This commit is contained in:
Reto Brunner 2020-05-04 19:17:23 +02:00 committed by Drew DeVault
parent d1600e4666
commit 8f2e5055ee
1 changed files with 12 additions and 0 deletions
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12
commands/msg/reply.go
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@ -89,8 +89,20 @@ func (reply) Execute(aerc *widgets.Aerc, args []string) error {
to = append(to, fmt.Sprintf("<%s@%s>", addr.Mailbox, addr.Host)) to = append(to, fmt.Sprintf("<%s@%s>", addr.Mailbox, addr.Host))
} }
} }
isMainRecipient := func(a *models.Address) bool {
for _, ta := range toList {
if ta.Mailbox == a.Mailbox && ta.Host == a.Host {
return true
}
}
return false
}
if replyAll { if replyAll {
for _, addr := range msg.Envelope.Cc { for _, addr := range msg.Envelope.Cc {
//dedupe stuff already in the to: header, no need to repeat
if isMainRecipient(addr) {
continue
}
cc = append(cc, addr.Format()) cc = append(cc, addr.Format())
} }
for _, addr := range msg.Envelope.To { for _, addr := range msg.Envelope.To {